C O N T E N T S:

- We have engineered this calculator to provide spans which will produce a solid built house with no bounce in the floors or any swags in the ceiling.(More…)

- Imposed loads varies from approximately 1.5 kN/m 2 (153 kg/m 2 ) in domestic buildings to approximately 1 0 kN/m 2 (1053 kg/m 2 ) in heavy industrial areas. 500 kg/m 2 is typical for office, storage space and similar.(More…)

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description: How to Calculate Floor Load Capacity _ EHow.com

**KEY TOPICS **

**[1] A 9K head would be more appropriate for your average cooling load, more than covering any north-side gains plus the 2400 BTU/hr of plug loads and ~300 BTU/hr of combined ceiling & floor (exaggerated floor load) they included in the Manual J. [2] The total load supportable (provided it?s uniformly distributed) by a floor is a product of the total square foot x capacity per square foot. [3] The service axial loads on the column are as follows: P_D 200 kips (dead load) P_L 300 kips (floor live load) P_S 150 kips (snow load) P_W plusminus 60 kips (wind land) P_E plusminus 40 kips (seismic load) Calculate the required nominal axial compression strength, P_w of the column. [4] Roof Loads: Dead load, D_roof 20 psf Snow load, S 40 psf Second-and Third-Floor Loads: Dead load, D_floor 40 psf Floor live load, L 50 psf Determine the dead load (with and without partitions) in pounds per square foot of floor area for a steel building floor system with W24 times 55 beams spaced at 6 ft. 0 in. o.c, and W30 times 116 girders spaced at 35 ft. on centers. [4] If the floor system is to be used as a heavy manufacturing plant, determine the controlling factored loads in kips/ft. for the design of the typical interior beam. [4] If you, as the building owner, can?t provide reliable loading data for the rigging work, the only recourse is for you or your rigger to involve an engineer knowledgeable about building design to analyze the floor structure for the loads that will be imposed during the rigging. [3] Before you ban 3,000 pound pallets or require people to shuffle across your floors with special weight distribution shoes, understand that floor structures themselves are designed to distribute those small, normal types of load concentrations expected of the design application, such as people walking across the floor. [3] A three-story building has columns spaced at 18 ft. in both orthogonal directions, and is subjected to the roof and floor loads listed below. [4] List the floor live loads for the following occupancies: Library stack rooms, Classrooms, Heavy storage, Light manufacturing, and Offices. [4] I am in the process of trying to track down the builder and then get ahold of more information regarding the spans, joists, safety load, and etc for the second floor. [5] How high can we stack these? Since it is sitting on a cement floor I assume this would be figured out as a static load. [6] They aren?t necessarily designed to handle the heavy loads we may need to move across your floor. [3] Both you the owner, and we the rigger, need to know if the floor will support the loads we?re moving across it. [3] This often requires us to move items across floors that may or may not have been designed to handle these types of loads. [3] A 20? x 50? room with a floor load capacity of 150 pounds per square (psf) foot means you have 1,000 square foot of floor space that can support 150 psf, or 15,000 pounds overall. [3] When we?re asked to quote a job or when we?re in the planning stages, we often receive information on floor loading expressed as “xx pounds per square foot load capacity”. [3]**

*We have engineered this calculator to provide spans which will produce a solid built house with no bounce in the floors or any swags in the ceiling.*When we ask questions about the supporting structure(s) or start to dig deeper, invariably someone will point out these floor loading capacity signs in the belief this is the single, critical piece of information we need to assess the ability of the floor to handle the loads. [3] The problem is, even if your total floor area can support the load, most loads aren?t uniformly distributed. [3] Floor load capacity applies to uniformly distributed loads, not concentrated or point loads. [3] The problem is, when planning a rigging project, though we may know we exceed the floor load capacity, we don?t yet know is where the weak link is. [3] Therefore, the occupant load of toilet rooms, locker rooms, meeting rooms, storage rooms, employee cafeterias and similar rooms (e.g. pre-function areas in assembly occupancies) may be omitted from the overall occupant load calculation of the floor (Section 27-358(c)). [7] The typical open office floor area would use an occupant load factor of 100 gross square feet per person. [7]

Their method, developed by Thomas M. Murray in the article “Building floor vibrations,” which appeared in Engineering Journal in 1991, calculates the fundamental frequency of the typical floor joists based on the floor joist stiffness, span and applied dead loads. [8] One floor joist manufacturer has suggested a live load deflection limit of L/480 for commercial floor spans up to 15 and a live load deflection limit of L/600 for spans above about 18 (between 15 and 18, they recommend a maximum live load deflection of about 3/8). [8]

A simple, prescriptive method of limiting vibration is to limit deflection, usually to higher criteria than is required by the IBC. This method, commonly called the uniformly distributed load (UDL) deflection method, attempts to control vibrations by limiting the static deflection of a floor under a uniform design load. [8]

Use the Wine Room Heat Load Calculator to determine the required cooling capacity (BTU/h) for your wine room. [9] This calculator should be used for PHIUS+ multifamily projects and follows the same protocol as the Multifamily Lighting and Miscellaneous Electric Loads (MEL) document. [10] This calculator should be used for PHIUS+ 2015 single-family projects using PHPP. It includes the equivalent allowance for primary energy from the PHIUS+ allowance in kWh/person/yr to kBTU/ft2.yr, the air-tightness equivalence for 0.05 cfm/ft2.envelope to ACH50, as well as the lighting and plug load calculations for single-family residences. [10]

Included here are two variations of the floor plan takeoffs and calculator showing the per floor method and per unit method. [10] [xyz-ihs snippet=”Amazon-Affiliate-Native-Ads”] Download the sample floor plans and two variations of the calculator here. [10]

Method B: The new Single Load Factor Method calculates the rentable space for each tenant using a uniform approach in measuring floor area. [11]

**POSSIBLY USEFUL **

**[12] If building is 24 x 24 and has trusses, and the load on the roof will be for 30 lb snow load and a ceiling with no storage will total out like this. [13] This will amount to twice as much load on the exterior walls compared to a building with a center wall. [13] The load on an outside wall with clear span trusses is exactly half the load on each wall. [13]**

*Imposed loads varies from approximately 1.5 kN/m 2 (153 kg/m 2 ) in domestic buildings to approximately 1 0 kN/m 2 (1053 kg/m 2 ) in heavy industrial areas. 500 kg/m 2 is typical for office, storage space and similar.*The highest is a fully loaded floor (70 pounds per square foot). [1] Loaded Pallet If you have a 44 pallet with a 3,000 pound motor on it, you have a floor loading of 187.5 pounds per square foot; already exceeding many 150 psf industrial floors. [3] When an engineer designs a building, they have to use something to calculate or specify floor loading, and “pounds per square foot” is usually it. [3]

There?s no rule-of-thumb that we can use to translate a “pounds per square foot” design load into an allowable load on skates, rollers, skids or tracks. [3] Concentrated dead and roof live loads on the typical roof girder in pounds per foot. [4] Determine the ultimate or factored load for a roof beam subjected to the following service loads: Dead load 29 psf (dead load) Show load 35 psf (snow load) Roof live load 20 psf Wind load 25 psf upward 15 psf downward Assuming a roof beam span of 30 ft. and a tributary width of 6 ft., determine the factored moment and shear. [4] Assuming a roof dead load of 30 psf and an essentially flat roof with a roof slope of 1/4 in/ft. for drainage, determine the following loads using the ASCE 7 load combinations. [4]

Determine the factored axial load or the required axial strength, P_s of a column in an office building with a regular roof configuration. [4] Total factored axial load on the typical corner column in pounds. [4] Using a column load summation table, calculate the cumulative axial loads on a typical interior column with and without live load reduction. [4] Determine the dead loads in kips/ft. for a typical interior beam and a typical interior girder. [4] The joists will be running perpendicular to the beam, which means you are distributing the load over several joists. [5] Generally (so long as you’re not truly creating a library) the additional load from a bookshelf or two, especially if distributed across multiple joists right next to a supporting wall, isn’t a problem. [5] According to the Manual-J those south and west windows combined contribute about 1800 BTU/hr to the peak load (credible), and most of your wall gains in the bedroom are probably another 400-500 BTU/hr (the 800 BTU/ht total is higher than reality, but the wall gains are primarily the unshaded south side.) [2] And, even with rapidly accumulating the errors to the high side piling on in the none-too-aggressive Manual-J inflating the load to an insanely high 13,385 BTU/hr the thing STILL comes in under the 13,800 output of the 18K Midea with a pair of 9K heads at 70F room temp (an HSPF test condition) and +5F outdoor temp, which is the same temperature difference as a 68F code-min interior temp and a +3F 99% outside design temp. [2] BTW:If the 7K heads were a Fujitsu proposal, note that the AOU18RLXFZ & AOU18RLXFZH units don’t modulate lower than 6800 BTU/hr, (more than 2x that of the Midea!), which is probably more than your design heat load, and will result in much higher cycling losses. [2]

Clearly the instantaneous load of running 4 burners on the stove while baking cookies on a 90F (the 1% outside design temp) day in July would overwhelm the capacity of the 9K, head, but you won’t be measurably better off with a 12K head. [2] If your load isn’t bigger than that at 38F, depending on how much the minimum capacity rises below that it’s in danger of cycling even into the 20sF. Putting the smallest and lowest-modulating heads possible gives it the best shot of at least coming close to making it’s HSPF numbers. [2] If your load is 5K @ 3F your load is 2500 BTU/hr @ 38F, which is near the low point of the minimum capacity curve. [2] They subtracted ZERO BTU/hr for plug loads & occupants? (They added some for the cooling load, which was right.) [2] You’re probably looking at less than 8000 BTU/hr of peak load for the entire condo, and that will be mostly in the bedroom, since the bedroom has both south and west facing windows soaking up late-in-the-day solar gains. [2] The true heat load is going to come in around 5000 BTU/hr @ 3F outdoors, give or take 1000 BTU/hr. [2]

The safe number of laden pallets per stack will depend on your pallet?s load capacities. [6] The latest question was regarding safe pallet stacking; specifically, how to safely calculate maximum pallet loads when stacking pallets. [6] At some point, you will be moving the juice onto the pallet and stacking the pallets, exceeding the dynamic load during the process could be disastrous and should be avoided. [6] Since our finished pallets are not subjected to other forces (Dynamic, conveyors, racking) the static load can exceed the dynamic rating of the pallet. [6]

What we find is that most newer homes, even in hot climates, have loads of 800 square feet per ton or more. [14] Without getting into detail, ciphering things out your way isn’t how psf live load works. [5] Or we can look up your total load rating if you know the species, grade, and rating of the joists. [5] The minimum speed on the 12K head is higher than the minimum speed on the 9k head, and even with just two 9k heads it is more than 2x oversized for the load. [2] Unless your load at 35F is above the minimum output, it may be cycling even when it’s in the low 20sF, and will not make it’s HSPF numbers due to the cycling losses. [2] When the minimum speed is higher than the immediate load the thing cycles on/off which makes it less efficient (and less comfortable.) [2]

No additional safety factors are required when load estimates are based on accurate information pertaining to the envelope construction and duct system efficiency. [2] Manual J calculations should be aggressive, which means that the designer should take full advantage of legitimate opportunities to minimize the size of estimated loads. [2] Even the same house rotated ninety degrees could vary in cooling load by 25% or more. [14] The loads you impose on a daily basis aren?t uniformly distributed either. [3]

Another occupant load factor listed is table and chair assembly use which is based on 15 net square feet per person. [7] For example: one occupant load factor listed is business which is based on 100 gross square feet per person. [7]

Contrary to what many people think, the occupant load factors outlined in the means of egress provisions of the Building Code are not based on the occupancy classification of the space. [7] As such, although the space is not an assembly occupancy (typically), the occupant load factor for table and chair seating must be used for this particular space. [7] The occupant load factor must be applied based on how the space will be used. [7] The application of occupant load factors to a space is often more of an art than it is a science. [7]

As always, clarifying unique uses and the application of an occupant load factor is recommended during the initial meeting with the plans examiner. [7] This is often confusing since the occupant load factors listed include assembly uses and business uses. [7]

Manual J HVAC load calculations determine how much heating and cooling a house actually needs. It used to be performed by engineers with pen, paper, and slide rules, now it’s almost always done with computer programs. [14] Because HVAC load calculations require time and attention to detail, so most HVAC contractors rely on rules of thumb to determine the sizes of the cooling systems they install. [14]

When we do a Manual J HVAC load calculation, we accurately enter all the relevant data, such as the home’s orientation, insulation levels, window types, areas of all the surfaces that gain or lose heat, and more. [14]

The load per pallet load cannot exceed: the pallet?s dynamic load capacity. [6] The total load of the stacked pallets cannot exceed: the pallet?s static load capacity. [6] As long as the total weight of the stacks doesn’t exceed the bottom pallet’s Static Load Capacity, you should be fine. [6] Once you have completed your stack, do not move any multiple pallet stacks unless the bottom pallet load is safely under the Dynamic Load capacity. [6]

On a typical office floor, which includes conference rooms and breakout areas, would you use 100 gross square feet throughout the entire floor because it is all business? Not necessarily, you have to look at how the space is being used. [7] Use a stud finder (unobtrusive) or a thin nail driven through ceiling drywall after locating joist by sounding with fist- to find the on center spacing of floor joists. [5] Measure joist height at stairs from floor to ceiling below- for joist depth. [5] Include the weights of 1-in. light-weight floor finish, suspended acoustical tile ceiling, mechanical and electrical equipment (assume an industrial building), and partitions. [4] The provision for non-simultaneous is incredibly beneficial for projects being designed in accordance with the 1968 Building Code since it allows for reduced overall required egress capacity on a floor (i.e. reduced exit stair width). [7] What do you think of console head units versus the high wall units? The console design may work out better for my floor plan. [2] At the very least, I want the 4 edges to continuously touch the floor) are against outside walls. [5] I want to make sure I do not put too much weight on the floor and space the weight out evenly. [5] The floor deck is 3.5-in. normal weight concrete on 1.5 in. times 20 ga. composite steel deck. [4] The floor mount consoles are preferred for heating dominated climates, since they draw in the coolest air in the room near the floor rather than warmer ceiling air. [2] There are many variables — such as the lumber species, the grade of the lumber, and the age of the lumber — that factor into calculating the amount a floor or ceiling system can carry. [15]

If it WERE the right way to do it.and my floor was rated 40 psf.and I stood on it with my feet both together.I would immediately end up in the basement since I would be occupying about one square foot and exerting 180 lbs downward force. [5] In order to give a general idea of my situation, I have read the lowest national level is 40 lb/sqft on average for the floor, in the room in the U.S. If I take 40 x 9.5 380lbs max in this book case. [5] If the weak link is the flooring, we can get around that by plating the floor or by bearing only on the floor beams. [3] If the floor beams are the weak links, then load-spreading to grab multiple beams is the way to go. [3]

Usually it’s based on square footage of conditioned floor area, and contractors in many areas generally use 400 to 600 square feet per ton as their rule. [14] It?s even typical for larger companies to post floor loading expressed in this fashion on different floors or areas of the plant. [3] Consequently the question of floor loading capacity comes up constantly, and it comes up regardless of whether the floor in question is a slab-on-grade, an upper floor or an open grate mezzanine deck. [3]

**RANKED SELECTED SOURCES **(15 source documents arranged by frequency of occurrence in the above report)

1. (20) Here?s my floor load capacity. That?s all you need, right? | AA Machinery

2. (17) Load calculation — ductless minisplit | GreenBuildingAdvisor.com

3. (14) Problem 2-3 A And B A.Determine The Factored Axial. | Chegg.com

4. (12) Top Five Building Code Questions Asked to a NYC Code Consultant

6. (9) Safe Pallet Stacking – Pallet Load Calculator | One Way Solutions

7. (6) Load Calculations | HVAC Design | Energy Vanguard

8. (4) Calculators & Protocols: Passive House Institute U.S.

9. (3) Wood Beam Calculator | What size do I need?

10. (3) What methods exist for checking floor vibration of light-frame wood structures? – WoodWorks

11. (2) Joist span calculator | Floor – Ceiling – LearnFraming.com

12. (1) How to Measure Commercial Square Footage: 13 Steps (with Pictures)

13. (1) Concrete Slab Load Capacity

14. (1) Calculating Maximum Load

15. (1) Wine Room Heat Load Calculator